Bengali] If A+B=90^(@) then prove that 1+(tanA)/(tanB)=sec^(2)A.

A+B=90^(@)impliesB=90^(@)-A :.1+(tanA)/(tanB)=1+(tanA)/(tan(90^(@)-A)) =1+(tanA)/(cotA)=1+tanA.tanA =1+tan^(2)A=sec^(2)A. Hence 1+(tanA)/(tanB)=sec^(2)A.

Prove that left( tan{A}-tan{B} right) ^{ 2 }+left( 1+tan{A}tan{B

Trigonometry. If a+b=90 then prove that root tanAtanB+tanAcotB

Bengali] If tanA=(1-cosB)/(sinB) , then tan2A=tanBdot

If A+B=90 ∘ then prove that root under tanA •tanB+tanB•cotA−sin

If a+b=90 prove that root of tanatanb+tanacotb/sinasecb

Bengali] If A+B=90^(@) then prove that 1+(tanA)/(tanB)=sec^(2)A.

If `A+B=90^@`, then : `tanA.tanB=`

If A + B = 90°, then (tan A tan B + tan A cot B)/(sin A sec B

Bengali] Prove that,tan(45^(@) + theta) = (1 + tan theta)/(1- tan the