What is the compressibility factor (Z) for 0.02 mole of a van der Waal

(d) (0.1+(1000xx(0.02)^(2))/(V^(2)))V=20xx0.02 =0.1V^(2)-0.4V+0.4=0 =V^(2)-4V+4=0 implies" "V=2L Z=(PV)/(nRT)=(0.1xx2)/(20xx0.02)=0.5

Filo Student Questions For CBSE , Grade 9 , Chemistry

Answered: Question 2: For the following parts,…

If `Z` is a compressibility factor, van der Waals' equation at low

al Gases f.a What is the compressibility factor (Z) 0.02 mole of a van der Waals' gas pressure of 0.1 atm. Assume the size of gas molecules is negligible. Given: RT =

3) 20%, 35% (4) 66.67%, 15% under sure is 37 At 37°C and 0.1 atm, the mass density of phosphorous vapour is 0.5 g/L. The molecular formula of phosphorus is take R =

Filo Student Questions For CBSE , Grade 9 , Chemistry

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Filo Student Questions For CBSE , Grade 9